Cevaplar

2012-12-01T23:32:22+02:00

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0
2012-12-01T23:42:01+02:00

k.(2,-3) + b.(6,6)=(0,0)

(2k,-3k)+ (6b,6b)=(0,0)

(2k+6b )+ (-3k+6b) = (0,0)

O halde : 2k+6b=0

             -3k+6b=0 burdan -5k=0 olur k=0 b=-6 olur.

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