Cevaplar

2012-10-05T22:30:12+03:00

pv(q'vp)' 

pv(q^p')

(pvq) ^ (pvp')

(pvq) ^ 1

= pvq 

0
2012-10-05T22:33:59+03:00

((p'^p)v(p'^q'))'

0^(pvq)=0dır 

0