Cevaplar

2012-10-09T17:43:46+03:00

 Feb 2011 – ... down vote favorite. $$y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leqx\leq 2$$ ... $$\int_{1}^{2}\sqrt{1+\frac{25}{36}x^{8}+\frac{9}{100x^{8}}}$$ ...

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