Cevaplar

2012-10-13T13:55:41+03:00

p' ∧ q'  v  p'∧p

  p' ∧q   v  0

p' ∧ q ............

0
2012-10-13T14:40:00+03:00

p'^(q'vp) = (p'^q) v (p'^p)

(p'^p=0)

(p'^q)v0= (p'^q)

 

0