Cevaplar

2012-10-24T12:13:40+03:00

(p^q)iseq =(p'vq')vq  
(q'vq)vp'
1vp'=1 

0
2012-10-24T12:16:43+03:00

(p^q)      q =(p'vq')vq  ////(q'vq)vp'/////1vp'=1 

0