Cevaplar

2012-10-26T16:20:53+03:00

B\C={n,c}

 

(AUC)n(AUB)={k,m,a,b,n,d,h}n{k,m,a,b,n,d,c}={k,m,a,b,n,d}

 

B-(AnC)={b,n,d,c}-{a,b}={n,d,c}

 

B'nC={k,m,a,h}n{a,b,d,h}={a,h}

 

Bn(AUC')={n,c,b,d}n[k,m,n,b,a,c}={n,c,b}

 

0